Statement:
The P Vs NP problem has a classic one line statement whether P=NP? Mathematically P Vs NP states
P = NP or P # NP i.e. whether or not P is equal to NP.
P states for polynomial time problems, problems that can be effectively solved in polynomial time by using a deterministic computer. Polynomial time means reasonable time in common terms and in technical terms it means that it is expressible in the form of a polynomial equation.
c P problems are characterized by a polynomial equation.
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i.e. P =CnK where n is the size of inputs or data and K is a positive integer. We call that these are of order K, i.e., O (K).
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Precisely
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P = Polynomial time i.e. time required to solve a P type problem.
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C = Arbitrary constant.
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n =Size of input or data.
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K =Order of P type problem.
Hence P represents a class of polynomial in which total numbers of outcomes are proportional to an integral power of inputs.
NP problems are those in which time required to get a solution is unreasonably large, though the cases are too much, to calculate each case itself may need trivial arithmetic only.
Only problem is number of cases, which are too large for a normal computer to handle fully in polynomial time.
NP literally means non- deterministic polynomial time problem i.e. the problem which can be solved in polynomial time only by a non deterministic computational machine only.
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A computer in polynomial or reasonable time cannot handle NP problem.
More often than not there are NP problems that may take centuries for a full solution by brute- force method i.e. by method of checking all options.