Calculus-Based Physics by Jeffrey W. Schnick - HTML preview

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Chapter 4 Conservation of Momentum

Example 4-2: A cannon of mass m , resting on a frictionless surface, fires a ball of

C

mass m . The ball is fired horizontally. The muzzle velocity is v . Find the velocity of

B

M

the ball and the recoil velocity of the cannon.

NOTE: This is an example of an anti-collision problem. It also involves the concept of relative

velocity. The muzzle velocity is the relative velocity between the ball and the cannon. It is the

velocity at which the two separate. If the velocity of the ball relative to the ground is v ′B to the

right, and the velocity of the cannon relative to the ground is v ′C to the left, then the velocity of

the ball relative to the cannon, also known as the muzzle velocity of the ball, is v

= v ′ +v ′ . In

M

B

C

cases not involving guns or cannons one typically uses the notation v

for "relative velocity" or,

rel

relating to the example at hand, v

for "velocity of the ball relative to the cannon."

BC

BEFORE

AFTER

v ′

v ′

C

m

B

C

m

B

p

Σ

= Σ

→ =

p′

0 = −m v ′ + m v ′

(1)

C C

B B

Also, from the definition of muzzle

velocity:

v =v ′ +v ′

M

B

C

v ′ =v −v ′

(2)

C

M

B

Substituting this result into equation (1)

yields:

0 = −m (v

−v ′ ) + m v ′

C

M

B

B B

0 = −m v

+ m v ′ + m v ′

C M

C B

B B

m v ′ + m v ′ = m v

mC

C

B

B B

C M

v

=v −

v

C

M

M

m + m

C

B

(m + m )v ′ = m v

C

B

B

C M

(m + m )v

− m v

C

B

M

C M

v ′ =

m

C

+

C

v ′ =

v

m

m

C

B

B

M

m + m

C

B

m v

+ m v − m v

C M

B M

C M

v ′ =

C

m + m

C

B

Now substitute this result into equation (2) above. This yields:

mB

v ′ =

v

C

M

m + m

C

B

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