Applied Finite Mathematics by Rupinder Sekhon, UniqU, LLC - HTML preview

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Chapter 8Linear Programing: The Simplex Method: Homework

MAXIMIZATION BY THE SIMPLEX METHOD

Solve the following linear programming problems using the simplex method.

Maximize z=x1+2x2+3x3

subject to _autogen-svg2png-0002.png

x 1 , x 2 , x 3 ≥ 0

x1=0, x2=9, x3=3, z=27
Exercise 2.

Maximize z=x1+2x2+x3

subject to _autogen-svg2png-0009.png

(8.1) x 1 , x 2 , x 3 ≥ 0

A farmer has 100 acres of land on which she plans to grow wheat and corn. Each acre of wheat requires 4 hours of labor and $20 of capital, and each acre of corn requires 16 hours of labor and $40 of capital. The farmer has at most 800 hours of labor and $2400 of capital available. If the profit from an acre of wheat is $80 and from an acre of corn is $100, how many acres of each crop should she plant to maximize her profit?

Wheat 80 acres, corn 20 acres; Profit $8400
Exercise 4.

A factory manufactures chairs, tables and bookcases each requiring the use of three operations: Cutting, Assembly, and Finishing. The first operation can be used at most 600 hours; the second at most 500 hours; and the third at most 300 hours. A chair requires 1 hour of cutting, 1 hour of assembly, and 1 hour of finishing; a table needs 1 hour of cutting, 2 hours of assembly, and 1 hour of finishing; and a bookcase requires 3 hours of cutting, 1 hour of assembly, and 1 hour of finishing. If the profit is $20 per unit for a chair, $30 for a table, and $25 for a bookcase, how many units of each should be manufactured to maximize profit?

The Acme Apple company sells its Pippin, Macintosh, and Fuji apples in mixes. Box I contains 4 apples of each kind; Box II contains 6 Pippin, 3 Macintosh, and 3 Fuji; and Box III contains no Pippin, 8 Macintosh and 4 Fuji apples. At the end of the season, the company has altogether 2800 Pippin, 2200 Macintosh, and 2300 Fuji apples left. Determine the maximum number of boxes that the company can make.

600 boxes; 400 of Box I, 200 of Box II, and none of Box III

MINIMIZATION BY THE SIMPLEX METHOD

In problems 1-2, convert each minimization problem into a maximization problem, the dual, and then solve by the simplex method.

Minimize z=6x1+8x2

subject to _autogen-svg2png-0012.png

x 1 , x 2 ≥ 0

Initial Simplex Tableau

image needed!!!!

Exercise 7.

Minimize z=5x1+6x2+7x3

subject to _autogen-svg2png-0015.png

x 1 , x 2 , x 3 ≥ 0

In the next two problems, convert each minimization problem into a maximization problem, the dual, and then solve by the simplex method.

Minimize z=4x1+3x2

subject to _autogen-svg2png-0018.png

x , x 2 ≥ 0

x1=4, x2=6, z=34
Exercise 9.

A diet is to contain at least 8 units of vitamins, 9 units of minerals, and 10 calories. Three foods, Food A, Food B, and Food C are to be purchased. Each unit of Food A provides 1 unit of vitamins, 1 unit of minerals, and 2 calories. Each unit of Food B provides 2 units of vitamins, 1 unit of minerals, and 1 calorie. Each unit of Food C provides 2 units of vitamins, 1 unit of minerals, and 2 calories. If Food A costs $3 per unit, Food B costs $2 per unit and Food C costs $3 per unit, how many units of each food should be purchased to keep costs at a minimum?

CHAPTER REVIEW

Solve the following linear programming problems using the simplex method.

Maximize z=5x1+3x2

subject to _autogen-svg2png-0024.png

x 1 ≥ 0 ; x 2 ≥ 0

x1=4, x2=8, y1=0, y2=0, z=44

Maximize z=5x1+8x2

subject to _autogen-svg2png-0032.png

x1≥0; x2≥0

x1=6, x2=12, y1=0, y2=0, z=126

Maximize z=2x1+3x2+x3

subject to _autogen-svg2png-0041.png

x 1 , x 2 , x 3 ≥ 0

x1=6, x2=4, x3=0, y1=0, y2=0, z=24

Maximize z=x1+6x2+8x3

subject to _autogen-svg2png-0050.png

x 1 , x 2 , x 3 ≥ 0

x1=450, x2=0, x3=1800, y1=750, y2=0, y3=0, z=14,850

Maximize z=6x1+8x2+5x3

subject to _autogen-svg2png-0060.png

x 1 , x 2 , x 3 ≥ 0

x1=0, x2=200, x3=1600, y1=0, y2=0, y3=1200, z=9600

Minimize z=12x1+10x2

subject to _autogen-svg2png-0070.png

x1≥0; x2≥0

x1=2, x2=4, z=64

Minimize z=4x1+6x2+7x3

subject to _autogen-svg2png-0077.png

(8.2) x 1 , x 2 , x 3 ≥ 0
x1=10, x2=10, x3=0, z=100

Minimize z=40x1+48x2+30x3

subject to _autogen-svg2png-0084.png

x 1 , x 2 , x 3 ≥ 0

x1=15/4, x2=35/4, x3=0, z=570