Waves and Optics by Paul Padley - HTML preview

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Chapter 5Electromagnetism Review

5.1Gauss' Law*

Gauss' Law

Now recall that flux is the scalar product of a vector field and a bit of surface_autogen-svg2png-0001.png where _autogen-svg2png-0002.png is some vector field and _autogen-svg2png-0003.png is a surface with the direction defined by the normal to the surface. For a series of connected surfaces _autogen-svg2png-0004.png the total flux through the combined surface would be the sum of the individual elements. For a vector field _autogen-svg2png-0005.png passing through the surface this leads to _autogen-svg2png-0006.png or when we go to infinitesimal areas _autogen-svg2png-0007.png Now lets consider a charge q in the middle of a sphere

_autogen-svg2png-0009.png but _autogen-svg2png-0010.png then Φ = 4 π k q _autogen-svg2png-0012.png So for this case we get _autogen-svg2png-0013.png We can generalize this to any closed surface. It is clear that for an arbitrary closed source, we can draw a sphere around the source within the arbitrary surface.. Think of bullets being fired from a gun, it is clear that the bullets originating in the inner sphere all pass through the outer surface and so one would expect that the flux would be the same. For example consider _autogen-svg2png-0014.png to be a patch on the inner sphere and _autogen-svg2png-0015.png to be its projection onto the outer arbitrary surface (with its normal making an angle θ with respect to the normal to _autogen-svg2png-0017.png

On the inner patch _autogen-svg2png-0018.png and at the outer patch _autogen-svg2png-0019.png So the two have equivalent fluxes.

Any electric field is the sum of fields of its individual sources so we can write _autogen-svg2png-0020.png or for charge distributed throughout the volume _autogen-svg2png-0021.png

Now we can apply Gauss' Theorem _autogen-svg2png-0022.png

The equation _autogen-svg2png-0023.png must be true for any volume of any size, shape or location. The only way that can be true is if:

_autogen-svg2png-0024.png Initially one may think that this is a much less clear way of posing Gauss' Law. In practice it is much more useful than the integral form. Given an arbitrary distribution of charge we can calculate the electric field anywhere in space.

Gauss' Law for Magnetism

We can consider the same arguments for magnetic fields however there is one major difference! There are no isolated source of magnetism. That is there are no magnetic monopoles. This is an experimental fact. In fact people continue to search for them but they have never been found. (Finding one would almost certainly be a discovery worthy of a Nobel Prize). So we have_autogen-svg2png-0025.png or _autogen-svg2png-0026.png

5.2Faraday's Law*

Faraday's Law

The magnetic flux is _autogen-svg2png-0001.pngA device that can maintain a potential difference, despite the flow of current is a source of electromotive force. (EMF) The definition is mathematically _autogen-svg2png-0002.pngFaraday's law states that_autogen-svg2png-0003.pngThis is simply an experimental fact.

Faraday's law could also be written_autogen-svg2png-0004.png

I will leave it as a problem to show that this can also be written_autogen-svg2png-0005.png

5.3Ampere's Law*

Ampere's Law (with displacement current)

For a steady current flowing through a straight wire, the magnetic field at a point at a perpendicular distance r from the wire, has a value _autogen-svg2png-0002.pngIf we integrate around the wire in a circle, then clearly we get _autogen-svg2png-0003.pngThis is true for irregular paths around the wire

_autogen-svg2png-0004.pngbut for small dl d l cosθ = rdφ _autogen-svg2png-0007.png In fact instead of current we use the surface integral of the current density J , which is the current per unit area _autogen-svg2png-0009.png Maxwell's great insight was to realize that this was incomplete. He reasoned that _autogen-svg2png-0010.png gives a _autogen-svg2png-0011.png field so we should expect that _autogen-svg2png-0012.png gives a _autogen-svg2png-0013.png field.

Figure (Displacement1.png)
Figure 5.1

Figure (Displacement2.png)
Figure 5.2

Figure (Displacement3.png)
Figure 5.3

Think of a capacitor in a simple circuit. We can draw a surface such as shown in the figure, with "surface 1" and take the line integral around the edge of the surface. Now look at surface 2, this will have the same line integral, but now the surface integral will be different. Clearly there is something incomplete with Ampere's law as formulated above. Maxwell re wrote Ampere's law _autogen-svg2png-0014.pngwhich solves the problem.

Again it is left as an exercise to show that _autogen-svg2png-0015.png

Maxwell's equations

Lets recall Maxwell's equations (in free space) in differential form _autogen-svg2png-0016.png

Solutions