Basics of Concrete Science by Professor L. Dvorkin, Professor O. Dvorkin - HTML preview

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,

8)

ag

.

c

ρc ρw ρf ag

.

ρ ag

.

c

.

b

Where C, W, F , C

– accordingly quantities of cement, water, fine and

ag

ag

coarse aggregates, kg/m3; ρ , ρ , ρ

и ρ

– accordingly specific gravity

c

w

f.ag

c.ag

(weight per unit absolute volume of ingredients of concrete) of cement,

water, fine and coarse aggregates, kg per liter; Р

– volume of voids in

c.ag

coarse aggregates, including space between particles; ρ

– bulk density

b.c.ag

of coarse aggregates, kg per liter.

Therefore:

1000

C

=

, (7.9)

ag

1

αρ ag

.

c

+

ρ ag

.

c

ρ ag

.

c

.

b

Fag = (1000 − C / ρ − W / ρ − C /

c

w

ag ρ ag

.

c

) ρ

(7